Comments on: No one can figure out this question! NOT EVEN PAID PH.D ONLINE PROFESSIONALS, PLEASE HELP!? http://getpaidtotakesurveyonline.info/get-paid-surveys/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/ For people who want to make money without working Sat, 05 May 2012 09:57:18 +0000 http://wordpress.org/?v=2.9.2 hourly 1 By: pisgahchemist http://getpaidtotakesurveyonline.info/get-paid-surveys/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/comment-page-1/#comment-7806 pisgahchemist Tue, 11 May 2010 05:28:52 +0000 http://getpaidtotakesurveyonline.info/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/#comment-7806 You're almost there: .... 2NO2 <==> 2NO + O2 I......8.0 ..............0.......0 E .. 4.2 .............3.8....1.9 K = [NO]^2 [O2] / [NO2]^2 K = 3.8^2 x 1.9 / 4.2^2 K = 1.56 Since you started with 8.0 mol/L of NO2 and at equilibrium you have 3.8 mol/L, then 3.8 mol/L of NO2 must have reacted. 8.0 - 3.8 = 4.2 mol/L which is the equilibrium concentration of the remaining NO2. You’re almost there:

…. 2NO2 < ==> 2NO + O2
I……8.0 …………..0…….0
E .. 4.2 ………….3.8….1.9

K = [NO]^2 [O2] / [NO2]^2
K = 3.8^2 x 1.9 / 4.2^2
K = 1.56

Since you started with 8.0 mol/L of NO2 and at equilibrium you have 3.8 mol/L, then 3.8 mol/L of NO2 must have reacted. 8.0 – 3.8 = 4.2 mol/L which is the equilibrium concentration of the remaining NO2.

]]> By: steve_geo1 http://getpaidtotakesurveyonline.info/get-paid-surveys/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/comment-page-1/#comment-7805 steve_geo1 Tue, 11 May 2010 04:54:45 +0000 http://getpaidtotakesurveyonline.info/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/#comment-7805 [NO] = 3.8M, [O2] = 1.9M, [NO2] = 8.0 - 3.8 = 4.2M K = (1.9)(14.4)/(17.6) = 15.5 [NO] = 3.8M, [O2] = 1.9M, [NO2] = 8.0 – 3.8 = 4.2M

K = (1.9)(14.4)/(17.6) = 15.5

]]> By: CK http://getpaidtotakesurveyonline.info/get-paid-surveys/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/comment-page-1/#comment-7804 CK Tue, 11 May 2010 04:10:14 +0000 http://getpaidtotakesurveyonline.info/no-one-can-figure-out-this-question-not-even-paid-ph-d-online-professionals-please-help/#comment-7804 This is probably wrong but try 0.475 mol/L....are you making sure to put the "mol/L" part on right because sometimes if you don't add the units it could say you are wrong. This is probably wrong but try 0.475 mol/L….are you making sure to put the “mol/L” part on right because sometimes if you don’t add the units it could say you are wrong.

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